# 源码中那一长串被注释的字符串，存在./equality.txt 文件中
with open('./equality.txt', 'r') as ff:
    content = ff.read()
import re
reg = re.compile('[a-z][A-Z]{3}[a-z][A-Z]{3}[a-z]')
res = reg.findall(content)
# print(res)
ans = [ss[4] for ss in res]
print("".join(ans))  # linkedlist, 注意后缀